Python Challenge攻略之Level 4

攻略：

首先根据提示从 linkedlist.html 转到 linkedlist.php，进入 level4
点击图片得到链接：http://www.pythonchallenge.com/pc/def/linkedlist.php?nothing=12345
网页内容为：and the next nothing is 44827
将 44827 替换 12345 得到网页链接：http://www.pythonchallenge.com/pc/def/linkedlist.php?nothing=44827
得到网页内容：and the next nothing is 45439
由此得知本关目的就在于利用程序循环重复以上过程直至得到结果。
中间可能会中断，可以根据提示修正。

代码：

#!/usr/bin/env/python
#coding:utf8
'''
Created on May 2, 2013

@author: killua
@url: http://www.pythonchallenge.com/pc/def/equality.html
@target: http://www.pythonchallenge.com/pc/def/linkedlist.html
'''

import urllib
import re

def next_page(nothing_no):
    try:
        text = urllib.urlopen('http://www.pythonchallenge.com/pc/def/linkedlist.php?nothing=%s' % nothing_no).read()
        print text
        m = re.match(r'[^\d]*(\d+)$', text)
        return m.groups()[0]
    except:
        return 'END'

if __name__ == '__main__':

    nothing_no = 12345
    #nothing_no = 16044 /2
    #nothing_no = 63579
    while True:
        nothing_no = next_page(nothing_no)
        if nothing_no.isdigit():
            continue
        else:
            break

完整代码：

Github：https://github.com/zhenlohuang/python-challenge